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abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Sun Jun 05, 2011 12:40 pm    Post subject: It's not a new idea, any time my friends, I welcome your ideas and suggestions, I will be very glad to do something for others _________________My YouTube channelLast edited by abdelhamid belaid on Sun May 19, 2013 5:39 pm; edited 1 time in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Mon Jun 06, 2011 11:41 pm    Post subject: a torus: _________________My YouTube channelLast edited by abdelhamid belaid on Sun May 19, 2013 5:46 pm; edited 1 time in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Thu Jun 09, 2011 12:31 am    Post subject: Hi all, for me this is the first pattern making over z=x*y surface _________________My YouTube channelLast edited by abdelhamid belaid on Sun May 19, 2013 5:48 pm; edited 2 times in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Sat Jun 11, 2011 1:47 pm    Post subject: here are patterned surfaces ( pattern(x,y)^2+f(x,y,z)^2-R^2=0 or generally F(pattern(x,y) , f(x,y,z))=0 ) _________________My YouTube channelLast edited by abdelhamid belaid on Sun May 19, 2013 5:50 pm; edited 2 times in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Fri Jun 17, 2011 11:44 am    Post subject: Hi all, It's just over new surfaces _________________My YouTube channelLast edited by abdelhamid belaid on Mon Nov 07, 2011 12:20 pm; edited 1 time in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Tue Jul 12, 2011 5:52 pm    Post subject: a torus: _________________My YouTube channelLast edited by abdelhamid belaid on Sun May 19, 2013 5:56 pm; edited 3 times in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Sun Jul 24, 2011 5:16 pm    Post subject: Hi all, A dodecahedron, of course we can get as much as we want faces (F(x,y,z,n)=0) _________________My YouTube channel
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Sat Aug 06, 2011 2:40 am    Post subject: taking straight lines instead of a single curved line: over z = sin(x) z = x^2 z = x*sin(x/3)/3 z = y*x^2/5 z = y*x^2/10 _________________My YouTube channelLast edited by abdelhamid belaid on Sun May 19, 2013 6:08 pm; edited 4 times in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Sat Aug 06, 2011 11:05 pm    Post subject: this is more explanation about my last method to make patterns over a z = f(x,y) surface: Let's call our step h, the new normal dimension N or N(f) or N(f, h) , we have z = 3/(1.5+x^2) (of course our formula is N(f, h)^2+y^2-R^2=0) I will every time change h (1, 1/2, 1/6, 1/10, 1/20, 1/100), I will get more and more a smooth shape (curved line), that means I will get a normal dimension (section is always orthogonal to the tangent or we can say to our surface) : h=1 h=0.5 h=0.25 h=0.166666666 h=0.1 h=0.05 h=0.01 more works: z = y*(x/4)^3 z= 3/(1.5+x^2+y^2) _________________My YouTube channelLast edited by abdelhamid belaid on Sun May 19, 2013 6:21 pm; edited 1 time in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Mon Aug 08, 2011 12:06 am    Post subject: normal dimension: _________________My YouTube channelLast edited by abdelhamid belaid on Sun May 19, 2013 6:26 pm; edited 3 times in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

Posted: Wed Aug 10, 2011 1:59 am    Post subject:

a tetrahedron :

 Code: max( z-2+tan(pi/3)*abs(x)  ,  tan(pi/3)*abs(y)-z-2  ) [x]: -3 , 3 [y]: -3 , 3 [z]: -2 , 2 I mean generally: max( z-h+tan(pi/3)*abs(x)  ,  tan(pi/3)*abs(y)-z-h  )

_________________
My YouTube channel

Last edited by abdelhamid belaid on Sun May 19, 2013 6:29 pm; edited 1 time in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Wed Aug 10, 2011 6:14 pm    Post subject: Also other patterned surfaces by the same method: z = 2*sin(x)^3*cos(y) z = sin(x)^3*cos(y)+cos(2*sqrt(x^2+y^2))/2 _________________My YouTube channel
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Thu Aug 11, 2011 9:15 pm    Post subject: another work: For a better view of the recent work: http://www.youtube.com/watch?v=zRn0Hq4fAgo http://www.youtube.com/watch?v=pA3h8EOgK-Q Some fun: _________________My YouTube channelLast edited by abdelhamid belaid on Sun May 19, 2013 6:31 pm; edited 3 times in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Sat Aug 13, 2011 12:01 am    Post subject: Now the same method and the same pattern over the surface sqrt(x^2+y^2) - 3 -sin(6*atan2(y,x))*cos(2*z)/3 =0 , as you see I've used the same method in polar coordinates also over sqrt(x^2+y^2) - 3 - cos(6*atan2(y,x)+z)/3 = 0 You can see them on YouTube: http://www.youtube.com/watch?v=4AGQOOJvFJU http://www.youtube.com/watch?v=0Fu66K0XsjM_________________My YouTube channelLast edited by abdelhamid belaid on Sun May 19, 2013 7:09 pm; edited 1 time in total
abdelhamid belaid

Joined: 13 Aug 2009
Posts: 170

 Posted: Tue Aug 16, 2011 1:02 pm    Post subject: The same pattern but it's around the origin this time It's over: z - cos(sqrt(x^2+y^2))*sin(x) = 0 _________________My YouTube channel
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