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inode
Joined: 27 Jan 2007 Posts: 127 Location: Austria

Posted: Sun Dec 02, 2007 10:33 pm Post subject: Xmas competition 


Hi all
Because of chrismas is coming I have an idea.
Lets make a little Xmas competition!
Everbody who has some formulas which looks approximately like a tree should publish it  here in this forum!
So please if YOU have a "tree formula" let us know about it...
Gerd 

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nextstep Site Admin
Joined: 06 Jan 2007 Posts: 538

Posted: Mon Dec 03, 2007 1:54 pm Post subject: 


Hi all,
Very good idea Gerd...and I like the competition's name
Hope we will have some Xifts before chrismas _________________ Cheers,
Abderrahman 

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François LE COAT
Joined: 03 Feb 2007 Posts: 27 Location: France

Posted: Mon Dec 03, 2007 5:19 pm Post subject: 


Within Eureka 2.12, I invented the formula of this kind of tree
that gives this kind of animation http://eureka.atari.org/walking.mov
That's designed for cylindrical coordinates described by
Code:  R^1 = mod(4z)*(4z)*sin(5*u+pi/2)^2
With U[ 0, 2*pi] And V[ 0, 4] 
But it gives me a syntax error, and I can't explain ?
Any idea ? _________________  archimedium
http://eureka.atari.org/ 

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nextstep Site Admin
Joined: 06 Jan 2007 Posts: 538

Posted: Mon Dec 03, 2007 6:09 pm Post subject: 


Hi all,
Waw..that's a beautiful chrismas tree François
For the formulas, the error message is for the function "mod". You can use the operator "%" to define the modulo function (ex : 5 % 2 = 1 ) but I'm not sure this is the function you're using since I cant reproduce the same shape you have... _________________ Cheers,
Abderrahman 

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François LE COAT
Joined: 03 Feb 2007 Posts: 27 Location: France

Posted: Mon Dec 03, 2007 6:42 pm Post subject: 


Quote:  Waw..that's a beautiful chrismas tree François 
You're kind Taha
Quote:  For the formulas, the error message is for the function "mod". You can use the operator "%" to define the modulo function (ex : 5 % 2 = 1 ) 
That's strange, because mod() is given on http://k3dsurf.sf.net. Is it a mistake ?
Quote:  but I'm not sure this is the function you're using since I can't reproduce the same shape you have ... 
I got Christmas Tree !
Code:  R^1 = ((4z)%1)*(4z)*sin(5*u+pi/2)^2
With U[ 0, 2*pi] And V[ 0, 4] 
Many thanks _________________  archimedium
http://eureka.atari.org/ 

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nextstep Site Admin
Joined: 06 Jan 2007 Posts: 538

Posted: Tue Dec 04, 2007 8:51 pm Post subject: 


Hi all,
Yes it's a mistake! I'll correct that in the next release.
Also, many thanks for your beautiful chrismas tree _________________ Cheers,
Abderrahman 

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inode
Joined: 27 Jan 2007 Posts: 127 Location: Austria

Posted: Sat Dec 08, 2007 2:51 pm Post subject: PG_Xmas_Tree_1 


my first tree  looks more like a corel  however here it is...
Code:  Name: PG_Xmas_Tree_1
/* Name: PG_Xmas_Tree_1 12/2007 Gerd Platl */
F(): 2(x^2+y^2)/550.135*zcos(sqrt(x^2+y^2))*sin(12*atan(y/x)) cos(12*atan(y/x))*sin(z) cos(z)*sin(sqrt(x^2+y^2))0.3*(cos(sqrt(x^2+y^2))*cos(15*atan(y/x)) cos(15*atan(y/x))*cos(z) cos(z)*cos(sqrt(x^2+y^2)))
[x]: 20 , 20
[y]: 20 , 20
[z]: 30 , 23.5
; 
Gerd
Last edited by inode on Sat Dec 08, 2007 4:38 pm; edited 1 time in total 

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inode
Joined: 27 Jan 2007 Posts: 127 Location: Austria

Posted: Sat Dec 08, 2007 4:01 pm Post subject: PG_Xmas_Tree_2 


hohoho  much work  but I've got it!
<k3dsurf  PovRay >
missing only some glitter spheres Gerd 

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nextstep Site Admin
Joined: 06 Jan 2007 Posts: 538

Posted: Sat Dec 08, 2007 10:32 pm Post subject: 


Hi all,
Ouuuuuups...you're a genius Gerd
That's trully the most beautiful mathematical Christmas tree I have ever seen. Congratulations _________________ Cheers,
Abderrahman 

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